What is the answer to solvefor x,y-sqrt(4-x^2)=0 ?

The answer to solvefor x,y-sqrt(4-x^2)=0 is x=sqrt(-y^2+4) {0<= y<= 2},x=-sqrt(-y^2+4) {0<= y<= 2}

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solvefor x,y-sqrt(4-x^2)=0

solve for

x, y - 4 - x^{2} = 0

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

Solution steps

y - 4 - x^{2} = 0

Move

y

to the right side

- 4 - x^{2} = - y

Square both sides:

4 - x^{2} = y^{2}

4 - x^{2} = y^{2}

Solve

4 - x^{2} = y^{2} : x = - y^{2} + 4, x = - - y^{2} + 4

x = - y^{2} + 4, x = - - y^{2} + 4

Verify Solutions:

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

The solutions are

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

x^{2} - 2 x - 2 x^{2} - 2 x + 2 = 1

7 - v = v - 35

x - 3 = x - 3

23 x + 105 = x + 9

What is the answer to solvefor x,y-sqrt(4-x^2)=0 ?
The answer to solvefor x,y-sqrt(4-x^2)=0 is x=sqrt(-y^2+4) {0<= y<= 2},x=-sqrt(-y^2+4) {0<= y<= 2}