What is the answer to solvefor x,2y+6=sqrt(x-3) ?

The answer to solvefor x,2y+6=sqrt(x-3) is x=4y^2+24y+39 {y>=-3}

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solvefor x,2y+6=sqrt(x-3)

solve for

x, 2 y + 6 = x - 3

x = 4 y^{2} + 24 y + 39 {y \geq - 3}

Solution steps

2 y + 6 = x - 3

Square both sides:

4 y^{2} + 24 y + 36 = x - 3

4 y^{2} + 24 y + 36 = x - 3

Solve

4 y^{2} + 24 y + 36 = x - 3 : x = 4 y^{2} + 24 y + 39

x = 4 y^{2} + 24 y + 39

Verify Solutions:

x = 4 y^{2} + 24 y + 39 {y \geq - 3}

The solution is

x = 4 y^{2} + 24 y + 39 {y \geq - 3}

2 x^{1.5} = 3 x^{1.5} - 1.5

x, x^{0.5} = 0.25 x

(- 2 x - 3) + (x + 3) = 3

0 = x - 2 x - 3

x + 6 x + 13 = - 1

What is the answer to solvefor x,2y+6=sqrt(x-3) ?
The answer to solvefor x,2y+6=sqrt(x-3) is x=4y^2+24y+39 {y>=-3}