What is the answer to 1=sqrt((0-x)^2+(0+x)^2) ?

The answer to 1=sqrt((0-x)^2+(0+x)^2) is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: 1=sqrt((0-x)^2+(0+x)^2)

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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1 = (0 - x)^{2} + (0 + x)^{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

1 = (0 - x)^{2} + (0 + x)^{2}

Square both sides:

1 = 2 x^{2}

1 = 2 x^{2}

Solve

1 = 2 x^{2} : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

4 x = 4 x - 1

2 x = x - 2

25 p + 1 = 24

4 x - \frac{2}{3} = 5

What is the answer to 1=sqrt((0-x)^2+(0+x)^2) ?
The answer to 1=sqrt((0-x)^2+(0+x)^2) is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: 1=sqrt((0-x)^2+(0+x)^2)
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))