What is the answer to 2x+2sqrt(x+1)sqrt(x+3)+4=0 ?

The answer to 2x+2sqrt(x+1)sqrt(x+3)+4=0 is No Solution for x\in\mathbb{R}

Solve for x: 2x+2sqrt(x+1)sqrt(x+3)+4=0

The solution is No Solution for x\in\mathbb{R}

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2 x + 2 x + 1 x + 3 + 4 = 0

No Solution for x \in R

Solution steps

2 x + 2 x + 1 x + 3 + 4 = 0

Remove square roots

4 x^{2} + 16 x + 12 = 4 x^{2} + 16 x + 16

Solve

4 x^{2} + 16 x + 12 = 4 x^{2} + 16 x + 16 :

No Solution

No Solution for x \in R

x - 3 x = 1

1 - \frac{x}{1 - x ^{2}} = 0

(x - 1)^{2} = [4 x - 4]^{2}

3 x + 1 - 4 = 0

What is the answer to 2x+2sqrt(x+1)sqrt(x+3)+4=0 ?
The answer to 2x+2sqrt(x+1)sqrt(x+3)+4=0 is No Solution for x\in\mathbb{R}
Solve for x: 2x+2sqrt(x+1)sqrt(x+3)+4=0
The solution is No Solution for x\in\mathbb{R}