What are the solutions to the equation x^2-3x-2.8=0 ?

The solutions to the equation x^2-3x-2.8=0 are x=(15+sqrt(505))/(10),x=(15-sqrt(505))/(10)

Find the zeros of x^2-3x-2.8=0

The zeros of x^2-3x-2.8=0 are x=(15+sqrt(505))/(10),x=(15-sqrt(505))/(10)

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x^{2} - 3 x - 2.8 = 0

x = \frac{15 + 505}{10}, x = \frac{15 - 505}{10}

Decimal Notation

x = 3.74722 \dots, x = - 0.74722 \dots

Solution steps

x^{2} - 3 x - 2.8 = 0

Multiply both sides by

10

10 x^{2} - 30 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 10 ( - 28 )}{2 \cdot 10}

(- 30)^{2} - 4 \cdot 10 (- 28) = 2505

x_{1, 2} = \frac{- ( - 30 ) \pm 2 505}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 2 505}{2 \cdot 10}, x_{2} = \frac{- ( - 30 ) - 2 505}{2 \cdot 10}

x = \frac{- ( - 30 ) + 2 505}{2 \cdot 10} : \frac{15 + 505}{10}

x = \frac{- ( - 30 ) - 2 505}{2 \cdot 10} : \frac{15 - 505}{10}

The solutions to the quadratic equation are:

x = \frac{15 + 505}{10}, x = \frac{15 - 505}{10}

- 4 (2 n - 6) < n + 6

\frac{13}{24} - \frac{5}{24}

(3 y^{- 5})^{- 3}

2 (e + 10) = 12

4 r^{2} + 4 r + 1

What are the solutions to the equation x^2-3x-2.8=0 ?
The solutions to the equation x^2-3x-2.8=0 are x=(15+sqrt(505))/(10),x=(15-sqrt(505))/(10)
Find the zeros of x^2-3x-2.8=0
The zeros of x^2-3x-2.8=0 are x=(15+sqrt(505))/(10),x=(15-sqrt(505))/(10)