What is the answer to sqrt(2x^2-4x)-x=0 ?

The answer to sqrt(2x^2-4x)-x=0 is x=4,x=0

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sqrt(2x^2-4x)-x=0

2 x^{2} - 4 x - x = 0

x = 4, x = 0

Solution steps

2 x^{2} - 4 x - x = 0

Remove square roots

2 x^{2} - 4 x = x^{2}

Solve

2 x^{2} - 4 x = x^{2} : x = 4, x = 0

x = 4, x = 0

Verify Solutions:

x = 4

True

, x = 0

True

The solutions are

x = 4, x = 0

4 x - 1 - x - 2 = 3

0 = - y^{2} - 16

x - 7 = x + 3

x + 5 = - 3

2 x + 15 + 2 = 5

What is the answer to sqrt(2x^2-4x)-x=0 ?
The answer to sqrt(2x^2-4x)-x=0 is x=4,x=0
Solve for x: sqrt(2x^2-4x)-x=0
The solution is x=4,x=0