What is the answer to x-4=sqrt(x^2+5x+6) ?

The answer to x-4=sqrt(x^2+5x+6) is No Solution for x\in\mathbb{R}

Solve for x: x-4=sqrt(x^2+5x+6)

The solution is No Solution for x\in\mathbb{R}

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x - 4 = x^{2} + 5 x + 6

No Solution for x \in R

Solution steps

x - 4 = x^{2} + 5 x + 6

Square both sides:

x^{2} - 8 x + 16 = x^{2} + 5 x + 6

x^{2} - 8 x + 16 = x^{2} + 5 x + 6

Solve

x^{2} - 8 x + 16 = x^{2} + 5 x + 6 : x = \frac{10}{13}

x = \frac{10}{13}

Verify Solutions:

x = \frac{10}{13}

False

The solution is

No Solution for x \in R

\frac{2 x + 4}{x ^{2} + 4 x} = 0

y, x = y - 3 + 3

x^{\frac{3}{4}} = \frac{1}{27}

7 x + 8 = - 8

(5 x + 6)^{\frac{1}{4}} = - 2

What is the answer to x-4=sqrt(x^2+5x+6) ?
The answer to x-4=sqrt(x^2+5x+6) is No Solution for x\in\mathbb{R}
Solve for x: x-4=sqrt(x^2+5x+6)
The solution is No Solution for x\in\mathbb{R}