What is the answer to 6=sqrt(x^2+3)-x ?

The answer to 6=sqrt(x^2+3)-x is x=-11/4

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6=sqrt(x^2+3)-x

6 = x^{2} + 3 - x

x = - \frac{11}{4}

Decimal Notation

x = - 2.75

Solution steps

6 = x^{2} + 3 - x

Remove square roots

36 + 12 x + x^{2} = x^{2} + 3

Solve

36 + 12 x + x^{2} = x^{2} + 3 : x = - \frac{11}{4}

x = - \frac{11}{4}

Verify Solutions:

x = - \frac{11}{4}

True

The solution is

x = - \frac{11}{4}

(2 x - 3)^{\frac{1}{2}} = x - 3

x - 3 = x - 9

3 = 2 x - 1

x^{2} + 2 x - 25 = x + 5

2 x - 1 - 5 = 0

What is the answer to 6=sqrt(x^2+3)-x ?
The answer to 6=sqrt(x^2+3)-x is x=-11/4
Solve for x: 6=sqrt(x^2+3)-x
The solution is x=-11/4