What is -3<= (4-2x)/5 <1 ?

The solution to -3<= (4-2x)/5 <1 is -1/2 <x<= 19/2

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-3<= (4-2x)/5 <1

- 3 \leq \frac{4 - 2 x}{5} < 1

- \frac{1}{2} < x \leq \frac{19}{2}

Interval Notation

(- \frac{1}{2}, \frac{19}{2}]

Decimal Notation

- 0.5 < x \leq 9.5

Solution steps

- 3 \leq \frac{4 - 2 x}{5} < 1

a \leq u < b

then

a \leq u and u < b

- 3 \leq \frac{4 - 2 x}{5} and \frac{4 - 2 x}{5} < 1

- 3 \leq \frac{4 - 2 x}{5} : x \leq \frac{19}{2}

\frac{4 - 2 x}{5} < 1 : x > - \frac{1}{2}

Combine the intervals

x \leq \frac{19}{2} and x > - \frac{1}{2}

Merge Overlapping Intervals

- \frac{1}{2} < x \leq \frac{19}{2}

11 7^{2} = x (x + 4)

x + 1 + 4 x = 11 + 12 x - 3

\frac{6}{3}

\frac{( 2 m ^{3} n ^{4} ) ^{2} \cdot 2 m ^{2}}{m ^{3} n ^{4}}

9 + (\frac{8}{2})^{3}