What is the answer to solvefor t,x=-sqrt(t+1) ?

The answer to solvefor t,x=-sqrt(t+1) is t=x^2-1 {x<= 0}

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solvefor t,x=-sqrt(t+1)

solve for

t, x = - t + 1

t = x^{2} - 1 {x \leq 0}

Solution steps

x = - t + 1

Divide both sides by

- 1

\frac{x}{- 1} = \frac{- t + 1}{- 1}

Simplify

- x = t + 1

Square both sides:

x^{2} = t + 1

x^{2} = t + 1

Solve

x^{2} = t + 1 : t = x^{2} - 1

t = x^{2} - 1

Verify Solutions:

t = x^{2} - 1 {x \leq 0}

The solution is

t = x^{2} - 1 {x \leq 0}

x - 1 = 6

\frac{y}{36 - y ^{2}} = 0

D^{- 4.87} = 50

What is the answer to solvefor t,x=-sqrt(t+1) ?
The answer to solvefor t,x=-sqrt(t+1) is t=x^2-1 {x<= 0}