What is the answer to y=sqrt(1-y^2) ?

The answer to y=sqrt(1-y^2) is y= 1/(sqrt(2))

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y=sqrt(1-y^2)

y = 1 - y^{2}

y = \frac{1}{2}

Decimal Notation

y = 0.70710 \dots

Solution steps

y = 1 - y^{2}

Square both sides:

y^{2} = 1 - y^{2}

y^{2} = 1 - y^{2}

Solve

y^{2} = 1 - y^{2} : y = \frac{1}{2}, y = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

Verify Solutions:

y = \frac{1}{2}

True

, y = - \frac{1}{2}

False

The solution is

y = \frac{1}{2}

2 {x + 1} + x = 7

\frac{1}{x} = 2 b

x - 2 = - 4 + x

4 x^{\frac{1}{2}} = 32

What is the answer to y=sqrt(1-y^2) ?
The answer to y=sqrt(1-y^2) is y= 1/(sqrt(2))
Solve for y: y=sqrt(1-y^2)
The solution is y= 1/(sqrt(2))