What is the answer to solvefor y,x=3+sqrt(-4-2y) ?

The answer to solvefor y,x=3+sqrt(-4-2y) is y=-(x^2-6x+13)/2 {x>= 3}

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solvefor y,x=3+sqrt(-4-2y)

solve for

y, x = 3 + - 4 - 2 y

y = - \frac{x ^{2} - 6 x + 13}{2} {x \geq 3}

Solution steps

x = 3 + - 4 - 2 y

Switch sides

3 + - 4 - 2 y = x

Move

3

to the right side

- 4 - 2 y = x - 3

Square both sides:

- 4 - 2 y = x^{2} - 6 x + 9

- 4 - 2 y = x^{2} - 6 x + 9

Solve

- 4 - 2 y = x^{2} - 6 x + 9 : y = - \frac{x ^{2} - 6 x + 13}{2}

y = - \frac{x ^{2} - 6 x + 13}{2}

Verify Solutions:

y = - \frac{x ^{2} - 6 x + 13}{2} {x \geq 3}

The solution is

y = - \frac{x ^{2} - 6 x + 13}{2} {x \geq 3}

x^{\frac{3}{2}} = 512

2 x = x 9 - x^{2}

2 x + 3 = 2 x + 3

- 2 x + 2 = 1 - x

x + x + 8 = 4

What is the answer to solvefor y,x=3+sqrt(-4-2y) ?
The answer to solvefor y,x=3+sqrt(-4-2y) is y=-(x^2-6x+13)/2 {x>= 3}