What is the answer to sqrt(3x^2+8x)=x+4 ?

The answer to sqrt(3x^2+8x)=x+4 is x=2sqrt(2),x=-2sqrt(2)

Solve for x: sqrt(3x^2+8x)=x+4

The solution is x=2sqrt(2),x=-2sqrt(2)

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3 x^{2} + 8 x = x + 4

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

3 x^{2} + 8 x = x + 4

Square both sides:

3 x^{2} + 8 x = x^{2} + 8 x + 16

3 x^{2} + 8 x = x^{2} + 8 x + 16

Solve

3 x^{2} + 8 x = x^{2} + 8 x + 16 : x = 22, x = - 22

x = 22, x = - 22

Verify Solutions:

x = 22

True

, x = - 22

True

The solutions are

x = 22, x = - 22

2 = C^{4}

3 (x + 2)^{\frac{3}{2}} = 375

8 - 8 x + 1 = x

x^{1.5} (x + 4) - 3 = 4.5 (x - 2)

x, 4 x + 41 = x + 5

What is the answer to sqrt(3x^2+8x)=x+4 ?
The answer to sqrt(3x^2+8x)=x+4 is x=2sqrt(2),x=-2sqrt(2)
Solve for x: sqrt(3x^2+8x)=x+4
The solution is x=2sqrt(2),x=-2sqrt(2)