What is the answer to sqrt(a^2+(a^2)/4)=1 ?

The answer to sqrt(a^2+(a^2)/4)=1 is a= 2/(sqrt(5)),a=-2/(sqrt(5))

Solve for a: sqrt(a^2+(a^2)/4)=1

The solution is a= 2/(sqrt(5)),a=-2/(sqrt(5))

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a^{2} + \frac{a ^{2}}{4} = 1

a = \frac{2}{5}, a = - \frac{2}{5}

Decimal Notation

a = 0.89442 \dots, a = - 0.89442 \dots

Solution steps

a^{2} + \frac{a ^{2}}{4} = 1

Square both sides:

a^{2} + \frac{a ^{2}}{4} = 1

a^{2} + \frac{a ^{2}}{4} = 1

Solve

a^{2} + \frac{a ^{2}}{4} = 1 : a = \frac{2}{5}, a = - \frac{2}{5}

a = \frac{2}{5}, a = - \frac{2}{5}

Verify Solutions:

a = \frac{2}{5}

True

, a = - \frac{2}{5}

True

The solutions are

a = \frac{2}{5}, a = - \frac{2}{5}

x + 4 = 6

y, y^{\frac{1}{3}} = x

x - 11 - 6 = 0

61 - 10 x = x - 7

2 x + 27 + 10 = 13

What is the answer to sqrt(a^2+(a^2)/4)=1 ?
The answer to sqrt(a^2+(a^2)/4)=1 is a= 2/(sqrt(5)),a=-2/(sqrt(5))
Solve for a: sqrt(a^2+(a^2)/4)=1
The solution is a= 2/(sqrt(5)),a=-2/(sqrt(5))