What are the solutions to the equation 2x^2+10x+12=0 ?

The solutions to the equation 2x^2+10x+12=0 are x=-2,x=-3

Find the zeros of 2x^2+10x+12=0

The zeros of 2x^2+10x+12=0 are x=-2,x=-3

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2 x^{2} + 10 x + 12 = 0

x = - 2, x = - 3

Solution steps

2 x^{2} + 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 12 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 2}, x_{2} = \frac{- 10 - 2}{2 \cdot 2}

x = \frac{- 10 + 2}{2 \cdot 2} : - 2

x = \frac{- 10 - 2}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

\frac{1}{6} \cdot \frac{2}{3}

f = (\frac{- 3}{5})

2.25 t + 5 = 13.5 t + 14

(2^{- 2})^{2}

lo g_{10} (\frac{1}{10})

What are the solutions to the equation 2x^2+10x+12=0 ?
The solutions to the equation 2x^2+10x+12=0 are x=-2,x=-3
Find the zeros of 2x^2+10x+12=0
The zeros of 2x^2+10x+12=0 are x=-2,x=-3