What is the answer to 5=sqrt(16+(-1-y)^2) ?

The answer to 5=sqrt(16+(-1-y)^2) is y=2,y=-4

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5=sqrt(16+(-1-y)^2)

5 = 16 + (- 1 - y)^{2}

y = 2, y = - 4

Solution steps

5 = 16 + (- 1 - y)^{2}

Square both sides:

25 = y^{2} + 2 y + 17

25 = y^{2} + 2 y + 17

Solve

25 = y^{2} + 2 y + 17 : y = 2, y = - 4

y = 2, y = - 4

Verify Solutions:

y = 2

True

, y = - 4

True

The solutions are

y = 2, y = - 4

10 + 3 x = x

2 y - 5 + 4 = 8

3 k - 20 = 15 - 2 k

y = 7

7 - x + 5 = x

What is the answer to 5=sqrt(16+(-1-y)^2) ?
The answer to 5=sqrt(16+(-1-y)^2) is y=2,y=-4
Solve for y: 5=sqrt(16+(-1-y)^2)
The solution is y=2,y=-4