What is the answer to sqrt(4x^2-4x+1)+(x+4)=x+7 ?

The answer to sqrt(4x^2-4x+1)+(x+4)=x+7 is x=2,x=-1

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sqrt(4x^2-4x+1)+(x+4)=x+7

4 x^{2} - 4 x + 1 + (x + 4) = x + 7

x = 2, x = - 1

Solution steps

4 x^{2} - 4 x + 1 + (x + 4) = x + 7

Remove square roots

4 x^{2} - 4 x + 1 = 9

Solve

4 x^{2} - 4 x + 1 = 9 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

True

The solutions are

x = 2, x = - 1

x 2 x - 7 = 1

\frac{x - 1}{x ^{2} - 2 x} = 0

x - 7 + 3 x + 1 = 10

4 x - 4 = 2

m + 2 + 1 = 7

What is the answer to sqrt(4x^2-4x+1)+(x+4)=x+7 ?
The answer to sqrt(4x^2-4x+1)+(x+4)=x+7 is x=2,x=-1
Solve for x: sqrt(4x^2-4x+1)+(x+4)=x+7
The solution is x=2,x=-1