What is the answer to sqrt((2x+3))^2+3-1=1 ?

The answer to sqrt((2x+3))^2+3-1=1 is No Solution for x\in\mathbb{R}

Solve for x: sqrt((2x+3))^2+3-1=1

The solution is No Solution for x\in\mathbb{R}

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(2 x + 3)^{2} + 3 - 1 = 1

No Solution for x \in R

Solution steps

((2 x + 3))^{2} + 3 - 1 = 1

Expand

(2 x + 3)^{2} + 3 - 1 : 2 x + 5

2 x + 5 = 1

Solve

2 x + 5 = 1 : x = - 2

x = - 2

Verify Solutions:

x = - 2

False

The solution is

No Solution for x \in R

7 x + 16 = 9 x - 8

x^{\frac{1}{2}} = 64

x, - f = x^{2} - x

u = 9 u - 14

2 = 12 - x^{2}

What is the answer to sqrt((2x+3))^2+3-1=1 ?
The answer to sqrt((2x+3))^2+3-1=1 is No Solution for x\in\mathbb{R}
Solve for x: sqrt((2x+3))^2+3-1=1
The solution is No Solution for x\in\mathbb{R}