What is the answer to solvefor x,xy^2+sqrt(xy)=0 ?

The answer to solvefor x,xy^2+sqrt(xy)=0 is x=0,x= 1/(y^3) {y 0}

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solvefor x,xy^2+sqrt(xy)=0

solve for

x, x y^{2} + x y = 0

x = 0, x = \frac{1}{y ^{3}} {y < 0 or y > 0}

Solution steps

x y^{2} + x y = 0

Remove square roots

x y = x^{2} y^{4}

Solve

x y = x^{2} y^{4} : x = 0, x = \frac{1}{y ^{3}}

x = 0, x = \frac{1}{y ^{3}}

Verify Solutions:

x = 0

True

, x = \frac{1}{y ^{3}} {y < 0 or y > 0}

The solutions are

x = 0, x = \frac{1}{y ^{3}} {y < 0 or y > 0}

x, x - 1 - x = - 7

3 z + 15 + 7 = z + 6

4 = a + 5

x + 8 = 7 x

x^{2} = x + 1

What is the answer to solvefor x,xy^2+sqrt(xy)=0 ?
The answer to solvefor x,xy^2+sqrt(xy)=0 is x=0,x= 1/(y^3) {y<0\lor y>0}