What is the answer to sqrt(w^2-5)+w=(1+6)/w ?

The answer to sqrt(w^2-5)+w=(1+6)/w is w= 7/3

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sqrt(w^2-5)+w=(1+6)/w

w^{2} - 5 + w = \frac{1 + 6}{w}

w = \frac{7}{3}

Decimal Notation

w = 2.33333 \dots

Solution steps

w^{2} - 5 + w = \frac{1 + 6}{w}

Multiply both sides by

w

w^{2} - 5 w + ww = \frac{1 + 6}{w} w

Simplify

w^{2} - 5 w + w^{2} = 7

Remove square roots

w^{4} - 5 w^{2} = 49 - 14 w^{2} + w^{4}

Solve

w^{4} - 5 w^{2} = 49 - 14 w^{2} + w^{4} : w = \frac{7}{3}, w = - \frac{7}{3}

w = \frac{7}{3}, w = - \frac{7}{3}

Verify Solutions:

w = \frac{7}{3}

True

, w = - \frac{7}{3}

False

The solution is

w = \frac{7}{3}

5 = 10 (0.38)^{0.2} K^{0.4}

x - 5 - 16 x = 0

(\frac{x}{1 - x})^{0.88} = 0.536

x - 1 - 3 x = 1

\frac{p + 2}{6} = - p

What is the answer to sqrt(w^2-5)+w=(1+6)/w ?
The answer to sqrt(w^2-5)+w=(1+6)/w is w= 7/3
Solve for w: sqrt(w^2-5)+w=(1+6)/w
The solution is w= 7/3