What is the answer to 2x^{3/2}-1=7 ?

The answer to 2x^{3/2}-1=7 is x=2\sqrt[3]{2}

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2x^{3/2}-1=7

2 x^{\frac{3}{2}} - 1 = 7

Decimal Notation

x = 2.51984 \dots

Solution steps

2 x^{\frac{3}{2}} - 1 = 7

Move

1

to the right side

2 x^{\frac{3}{2}} = 8

Divide both sides by

2

x^{\frac{3}{2}} = 4

Take both sides of the equation to the power of

2 : x^{3} = 16

x^{3} = 16

Solve

Verify Solutions:

True

The solution is

x^{0.75} = 20

18 (\frac{9 x}{3 x + 5}) = 30

(- 8 + 5)^{2} + (x - 0)^{2} = 7

What is the answer to 2x^{3/2}-1=7 ?
The answer to 2x^{3/2}-1=7 is x=2\sqrt[3]{2}
Solve for x: 2x^{3/2}-1=7
The solution is x=2\sqrt[3]{2}