What is the answer to solvefor y,2p=\sqrt[3]{6y-8} ?

The answer to solvefor y,2p=\sqrt[3]{6y-8} is y=(4(p^3+1))/3

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solvefor y,2p=\sqrt[3]{6y-8}

y = \frac{4 ( p ^{3} + 1 )}{3}

Solution steps

Take both sides of the equation to the power of

3 : 8 p^{3} = 6 y - 8

8 p^{3} = 6 y - 8

Solve

8 p^{3} = 6 y - 8 : y = \frac{4 ( p ^{3} + 1 )}{3}

y = \frac{4 ( p ^{3} + 1 )}{3}

Verify Solutions:

y = \frac{4 ( p ^{3} + 1 )}{3}

True

The solution is

y = \frac{4 ( p ^{3} + 1 )}{3}

x + 34 = x + 4

x, y = 2 x + 1

x + 3 + 6 - 5 x + 3 = 0

3 x - 16 x + 5 = 0

What is the answer to solvefor y,2p=\sqrt[3]{6y-8} ?
The answer to solvefor y,2p=\sqrt[3]{6y-8} is y=(4(p^3+1))/3