What is the answer to solvefor y,\sqrt[3]{(y+1)}=x ?

The answer to solvefor y,\sqrt[3]{(y+1)}=x is y=x^3-1

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solvefor y,\sqrt[3]{(y+1)}=x

solve for

y = x^{3} - 1

Solution steps

Take both sides of the equation to the power of

3 : y + 1 = x^{3}

y + 1 = x^{3}

Solve

y + 1 = x^{3} : y = x^{3} - 1

y = x^{3} - 1

Verify Solutions:

y = x^{3} - 1

True

The solution is

y = x^{3} - 1

3 x - 1 = 2 x + 4

x - x - 2 = 1

21 x + 1 - 5 = x

y + 7 = 6

(\frac{x}{1 - x})^{0.88} = 0.965

What is the answer to solvefor y,\sqrt[3]{(y+1)}=x ?
The answer to solvefor y,\sqrt[3]{(y+1)}=x is y=x^3-1