What is the answer to 1000sqrt(p)+200p=12000 ?

The answer to 1000sqrt(p)+200p=12000 is p=(145-5sqrt(265))/2

Solve for p: 1000sqrt(p)+200p=12000

The solution is p=(145-5sqrt(265))/2

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1000 p + 200 p = 12000

p = \frac{145 - 5 265}{2}

Decimal Notation

p = 31.80294 \dots

Solution steps

1000 p + 200 p = 12000

Remove square roots

1000000 p = 144000000 - 4800000 p + 40000 p^{2}

Solve

1000000 p = 144000000 - 4800000 p + 40000 p^{2} : p = \frac{145 + 5 265}{2}, p = \frac{145 - 5 265}{2}

p = \frac{145 + 5 265}{2}, p = \frac{145 - 5 265}{2}

Verify Solutions:

p = \frac{145 + 5 265}{2}

False

, p = \frac{145 - 5 265}{2}

True

The solution is

p = \frac{145 - 5 265}{2}

6 6 x = x^{2}

x = (1.62 x)^{\frac{1}{12}}

1 - x + 12 + x - 5 = 0

x^{2} = 3 - 2 x^{2} - 3

What is the answer to 1000sqrt(p)+200p=12000 ?
The answer to 1000sqrt(p)+200p=12000 is p=(145-5sqrt(265))/2
Solve for p: 1000sqrt(p)+200p=12000
The solution is p=(145-5sqrt(265))/2