What is the answer to 2\sqrt[3]{x-4}=\sqrt[3]{2x+4} ?

The answer to 2\sqrt[3]{x-4}=\sqrt[3]{2x+4} is x=6

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2\sqrt[3]{x-4}=\sqrt[3]{2x+4}

x = 6

Solution steps

Take both sides of the equation to the power of

3 : 8 x - 32 = 2 x + 4

8 x - 32 = 2 x + 4

Solve

8 x - 32 = 2 x + 4 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

x + 1 = 5

x + 1 = 4

2 x^{\frac{3}{2}} - 6 = 0

\frac{3}{x + 1} = 3

x + 9 = 9

What is the answer to 2\sqrt[3]{x-4}=\sqrt[3]{2x+4} ?
The answer to 2\sqrt[3]{x-4}=\sqrt[3]{2x+4} is x=6
Solve for x: 2\sqrt[3]{x-4}=\sqrt[3]{2x+4}
The solution is x=6