What is the answer to sqrt(x^2-5)-sqrt(4-x)=0 ?

The answer to sqrt(x^2-5)-sqrt(4-x)=0 is x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

Solve for x: sqrt(x^2-5)-sqrt(4-x)=0

The solution is x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

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x^{2} - 5 - 4 - x = 0

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

Decimal Notation

x = 2.54138 \dots, x = - 3.54138 \dots

Solution steps

x^{2} - 5 - 4 - x = 0

Remove square roots

x^{2} - 5 = 4 - x

Solve

x^{2} - 5 = 4 - x : x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

Verify Solutions:

x = \frac{- 1 + 37}{2}

True

, x = \frac{- 1 - 37}{2}

True

The solutions are

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

9 - 11 x = 8

y - 1 = 2 y + 1

\frac{0.02}{n} = 0.001

x + 15 = 2 x

What is the answer to sqrt(x^2-5)-sqrt(4-x)=0 ?
The answer to sqrt(x^2-5)-sqrt(4-x)=0 is x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2
Solve for x: sqrt(x^2-5)-sqrt(4-x)=0
The solution is x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2