What is the answer to 9=sqrt((0+6)^2+(y-4)^2) ?

The answer to 9=sqrt((0+6)^2+(y-4)^2) is y=4+3sqrt(5),y=4-3sqrt(5)

Solve for y: 9=sqrt((0+6)^2+(y-4)^2)

The solution is y=4+3sqrt(5),y=4-3sqrt(5)

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9 = (0 + 6)^{2} + (y - 4)^{2}

y = 4 + 35, y = 4 - 35

Decimal Notation

y = 10.70820 \dots, y = - 2.70820 \dots

Solution steps

9 = (0 + 6)^{2} + (y - 4)^{2}

Square both sides:

81 = y^{2} - 8 y + 52

81 = y^{2} - 8 y + 52

Solve

81 = y^{2} - 8 y + 52 : y = 4 + 35, y = 4 - 35

y = 4 + 35, y = 4 - 35

Verify Solutions:

y = 4 + 35

True

, y = 4 - 35

True

The solutions are

y = 4 + 35, y = 4 - 35

7 x + 57 = 2 x + 6

4 x^{2} - 4 x + 1 + (x + 4) = a + 7

7 x + 8 = x + 2

x - 5 + 1 = x

7 x - 5 = 3 x

What is the answer to 9=sqrt((0+6)^2+(y-4)^2) ?
The answer to 9=sqrt((0+6)^2+(y-4)^2) is y=4+3sqrt(5),y=4-3sqrt(5)
Solve for y: 9=sqrt((0+6)^2+(y-4)^2)
The solution is y=4+3sqrt(5),y=4-3sqrt(5)