What is the answer to sqrt(2x)=sqrt(4x+9)-3 ?

The answer to sqrt(2x)=sqrt(4x+9)-3 is x=18,x=0

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sqrt(2x)=sqrt(4x+9)-3

2 x = 4 x + 9 - 3

x = 18, x = 0

Solution steps

2 x = 4 x + 9 - 3

Remove square roots

4 x^{2} + 72 x + 324 = 144 x + 324

Solve

4 x^{2} + 72 x + 324 = 144 x + 324 : x = 18, x = 0

x = 18, x = 0

Verify Solutions:

x = 18

True

, x = 0

True

The solutions are

x = 18, x = 0

x - 5 + 2 = 7

2 s + 4 = - \frac{1}{2} - s

x - 8 - 7 x = 0

y, x = 8 y - y^{2}

(y^{2} - 9)^{\frac{1}{2}} = 9 - y

What is the answer to sqrt(2x)=sqrt(4x+9)-3 ?
The answer to sqrt(2x)=sqrt(4x+9)-3 is x=18,x=0
Solve for x: sqrt(2x)=sqrt(4x+9)-3
The solution is x=18,x=0