What is the answer to sqrt(x^2-2x+1)+x^2=1 ?

The answer to sqrt(x^2-2x+1)+x^2=1 is x=0,x=1

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sqrt(x^2-2x+1)+x^2=1

x^{2} - 2 x + 1 + x^{2} = 1

x = 0, x = 1

Solution steps

x^{2} - 2 x + 1 + x^{2} = 1

Remove square roots

x^{2} - 2 x + 1 = 1 - 2 x^{2} + x^{4}

Solve

x^{2} - 2 x + 1 = 1 - 2 x^{2} + x^{4} : x = 0, x = 1, x = - 2

x = 0, x = 1, x = - 2

Verify Solutions:

x = 0

True

, x = 1

True

, x = - 2

False

The solutions are

x = 0, x = 1

4 = (0.5 k)^{0.5} \cdot k

50 = \frac{2 x}{2200}

(6 x - 2)^{\frac{3}{2}} - 7 = 1

- 1 = - \frac{3}{2 t}

(2 x^{\frac{3}{2}})^{4} = 128

What is the answer to sqrt(x^2-2x+1)+x^2=1 ?
The answer to sqrt(x^2-2x+1)+x^2=1 is x=0,x=1
Solve for x: sqrt(x^2-2x+1)+x^2=1
The solution is x=0,x=1