What is the answer to solvefor x,y^2=sqrt(x-1) ?

The answer to solvefor x,y^2=sqrt(x-1) is x=y^4+1

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solvefor x,y^2=sqrt(x-1)

solve for

x, y^{2} = x - 1

x = y^{4} + 1

Solution steps

y^{2} = x - 1

Square both sides:

y^{4} = x - 1

y^{4} = x - 1

Solve

y^{4} = x - 1 : x = y^{4} + 1

x = y^{4} + 1

Verify Solutions:

x = y^{4} + 1

True

The solution is

x = y^{4} + 1

0.2 x^{\frac{1}{3}} = 0.062 x

x, f^{- 1} (x) = 2 x

x + x - 12 = 2

5 = x^{2} + 3^{2}

x^{2} - 16 x = 12

What is the answer to solvefor x,y^2=sqrt(x-1) ?
The answer to solvefor x,y^2=sqrt(x-1) is x=y^4+1