What is the answer to 2*sqrt(x-1)+sqrt(x+3)=2 ?

The answer to 2*sqrt(x-1)+sqrt(x+3)=2 is x=1

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2*sqrt(x-1)+sqrt(x+3)=2

2 \cdot x - 1 + x + 3 = 2

x = 1

Solution steps

2 x - 1 + x + 3 = 2

Remove square roots

9 x^{2} - 66 x + 121 = 16 x + 48

Solve

9 x^{2} - 66 x + 121 = 16 x + 48 : x = \frac{73}{9}, x = 1

x = \frac{73}{9}, x = 1

Verify Solutions:

x = \frac{73}{9}

False

, x = 1

True

The solution is

x = 1

4 y + 13 = 6 y + 7

x - 3 = 13 x + 9

16 - x^{4} = 0

q^{0.2} (q - 6) - 3 = 5

What is the answer to 2*sqrt(x-1)+sqrt(x+3)=2 ?
The answer to 2*sqrt(x-1)+sqrt(x+3)=2 is x=1
Solve for x: 2*sqrt(x-1)+sqrt(x+3)=2
The solution is x=1