What is the answer to sqrt(1-x^2)=ax ?

The answer to sqrt(1-x^2)=ax is x= 1/(sqrt(1+a^2)) {a>= 0},x=-1/(sqrt(1+a^2)) {a<= 0}

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sqrt(1-x^2)=ax

1 - x^{2} = a x

x = \frac{1}{1 + a ^{2}} {a \geq 0}, x = - \frac{1}{1 + a ^{2}} {a \leq 0}

Solution steps

1 - x^{2} = a x

Square both sides:

1 - x^{2} = a^{2} x^{2}

1 - x^{2} = a^{2} x^{2}

Solve

1 - x^{2} = a^{2} x^{2} : x = \frac{1}{1 + a ^{2}}, x = - \frac{1}{1 + a ^{2}}

x = \frac{1}{1 + a ^{2}}, x = - \frac{1}{1 + a ^{2}}

Verify Solutions:

x = \frac{1}{1 + a ^{2}} {a \geq 0}, x = - \frac{1}{1 + a ^{2}} {a \leq 0}

The solutions are

x = \frac{1}{1 + a ^{2}} {a \geq 0}, x = - \frac{1}{1 + a ^{2}} {a \leq 0}

x = 5 + (3 x - 11)^{\frac{1}{2}}

3 x - 7 = 5 x + 5

(3 x + 4) - (x - 3) = 3

1.93 = 2 π \frac{l}{9.8}

What is the answer to sqrt(1-x^2)=ax ?
The answer to sqrt(1-x^2)=ax is x= 1/(sqrt(1+a^2)) {a>= 0},x=-1/(sqrt(1+a^2)) {a<= 0}