What is the answer to \sqrt[3]{x^3+3x^2}=x+1 ?

The answer to \sqrt[3]{x^3+3x^2}=x+1 is x=-1/3

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\sqrt[3]{x^3+3x^2}=x+1

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

Take both sides of the equation to the power of

3 : x^{3} + 3 x^{2} = x^{3} + 3 x^{2} + 3 x + 1

x^{3} + 3 x^{2} = x^{3} + 3 x^{2} + 3 x + 1

Solve

x^{3} + 3 x^{2} = x^{3} + 3 x^{2} + 3 x + 1 : x = - \frac{1}{3}

x = - \frac{1}{3}

Verify Solutions:

x = - \frac{1}{3}

True

The solution is

x = - \frac{1}{3}

1.19 = \frac{d}{2}

10 + 24 k = 13 1 + k^{2}

x^{\frac{3}{2}} = 32

What is the answer to \sqrt[3]{x^3+3x^2}=x+1 ?
The answer to \sqrt[3]{x^3+3x^2}=x+1 is x=-1/3
Solve for x: \sqrt[3]{x^3+3x^2}=x+1
The solution is x=-1/3