What is the answer to x=sqrt(2x-x^2) ?

The answer to x=sqrt(2x-x^2) is x=0,x=1

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x=sqrt(2x-x^2)

x = 2 x - x^{2}

x = 0, x = 1

Solution steps

x = 2 x - x^{2}

Square both sides:

x^{2} = 2 x - x^{2}

x^{2} = 2 x - x^{2}

Solve

x^{2} = 2 x - x^{2} : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

True

, x = 1

True

The solutions are

x = 0, x = 1

\frac{m}{10} = 10

x = 4 + 5 x - 26

3 x + 1 = 2 x + 6

x^{2} - 2 x + 4 = x - 1