What are the solutions to the equation 12x^2-13x+3=0 ?

The solutions to the equation 12x^2-13x+3=0 are x= 3/4 ,x= 1/3

Find the zeros of 12x^2-13x+3=0

The zeros of 12x^2-13x+3=0 are x= 3/4 ,x= 1/3

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12 x^{2} - 13 x + 3 = 0

x = \frac{3}{4}, x = \frac{1}{3}

Decimal Notation

x = 0.75, x = 0.33333 \dots

Solution steps

12 x^{2} - 13 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

(- 13)^{2} - 4 \cdot 12 \cdot 3 = 5

x_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 12}, x_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 12}

x = \frac{- ( - 13 ) + 5}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 13 ) - 5}{2 \cdot 12} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = \frac{1}{3}

54 s^{3} + 2

136 - 76 + 6

(x - 3)^{2} - 64 y^{4}

2 x + 4 x

\frac{1}{65} (3) (23)^{2} - (\frac{1}{6} (3) (- 4)^{2})

What are the solutions to the equation 12x^2-13x+3=0 ?
The solutions to the equation 12x^2-13x+3=0 are x= 3/4 ,x= 1/3
Find the zeros of 12x^2-13x+3=0
The zeros of 12x^2-13x+3=0 are x= 3/4 ,x= 1/3