What is the answer to sqrt(k-2)=sqrt(2k+3)-2 ?

The answer to sqrt(k-2)=sqrt(2k+3)-2 is k=11,k=3

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sqrt(k-2)=sqrt(2k+3)-2

k - 2 = 2 k + 3 - 2

k = 11, k = 3

Solution steps

k - 2 = 2 k + 3 - 2

Remove square roots

k^{2} + 18 k + 81 = 32 k + 48

Solve

k^{2} + 18 k + 81 = 32 k + 48 : k = 11, k = 3

k = 11, k = 3

Verify Solutions:

k = 11

True

, k = 3

True

The solutions are

k = 11, k = 3

1 = 2 π \frac{L}{0.16327}

x + 7 + 2 = 3 - x

- 54 = 10 - (x - 10)^{\frac{3}{2}}

x^{2} - 6 x = 13 x^{2} - 6 x - 36

What is the answer to sqrt(k-2)=sqrt(2k+3)-2 ?
The answer to sqrt(k-2)=sqrt(2k+3)-2 is k=11,k=3
Solve for k: sqrt(k-2)=sqrt(2k+3)-2
The solution is k=11,k=3