What is the answer to sqrt(4x^2)+x+4=13 ?

The answer to sqrt(4x^2)+x+4=13 is x=-9,x=3

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sqrt(4x^2)+x+4=13

4 x^{2} + x + 4 = 13

x = - 9, x = 3

Solution steps

4 x^{2} + x + 4 = 13

Remove square roots

4 x^{2} = x^{2} - 18 x + 81

Solve

4 x^{2} = x^{2} - 18 x + 81 : x = - 9, x = 3

x = - 9, x = 3

Verify Solutions:

x = - 9

True

, x = 3

True

The solutions are

x = - 9, x = 3

2 x = 24

3 x - 1 = 0

2 x = - 3

50 w = 202

What is the answer to sqrt(4x^2)+x+4=13 ?
The answer to sqrt(4x^2)+x+4=13 is x=-9,x=3
Solve for x: sqrt(4x^2)+x+4=13
The solution is x=-9,x=3