What is the answer to solvefor y,x=\sqrt[3]{y-2} ?

The answer to solvefor y,x=\sqrt[3]{y-2} is y=x^3+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,x=\sqrt[3]{y-2}

solve for

y = x^{3} + 2

Solution steps

Take both sides of the equation to the power of

3 : x^{3} = y - 2

x^{3} = y - 2

Solve

x^{3} = y - 2 : y = x^{3} + 2

y = x^{3} + 2

Verify Solutions:

y = x^{3} + 2

True

The solution is

y = x^{3} + 2

x - 1 - 5 = x - 8

9 x - 14 = x

x + 2 = 1 - 2 x + 5

What is the answer to solvefor y,x=\sqrt[3]{y-2} ?
The answer to solvefor y,x=\sqrt[3]{y-2} is y=x^3+2