What is the answer to 10=sqrt(x^2+(x+2)^2) ?

The answer to 10=sqrt(x^2+(x+2)^2) is x=6,x=-8

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10=sqrt(x^2+(x+2)^2)

10 = x^{2} + (x + 2)^{2}

x = 6, x = - 8

Solution steps

10 = x^{2} + (x + 2)^{2}

Square both sides:

100 = 2 x^{2} + 4 x + 4

100 = 2 x^{2} + 4 x + 4

Solve

100 = 2 x^{2} + 4 x + 4 : x = 6, x = - 8

x = 6, x = - 8

Verify Solutions:

x = 6

True

, x = - 8

True

The solutions are

x = 6, x = - 8

x (1 - x) = 2 x - x (1 - x)

6 = 49 - x^{2}

x^{- 0.5} = 10.23

2 1 - r = 1 + 2 r - 1

What is the answer to 10=sqrt(x^2+(x+2)^2) ?
The answer to 10=sqrt(x^2+(x+2)^2) is x=6,x=-8
Solve for x: 10=sqrt(x^2+(x+2)^2)
The solution is x=6,x=-8