What is the answer to G(x)=sqrt(x^2-16) ?

The answer to G(x)=sqrt(x^2-16) is x=sqrt(-(16)/(G^2-1)) {0<= G<1},x=-sqrt(-(16)/(G^2-1)) {-1<G<= 0}

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G(x)=sqrt(x^2-16)

G (x) = x^{2} - 16

x = - \frac{16}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{16}{G ^{2} - 1} {- 1 < G \leq 0}

Solution steps

G (x) = x^{2} - 16

Square both sides:

G^{2} x^{2} = x^{2} - 16

G^{2} x^{2} = x^{2} - 16

Solve

G^{2} x^{2} = x^{2} - 16 : x = - \frac{16}{G ^{2} - 1}, x = - - \frac{16}{G ^{2} - 1}

x = - \frac{16}{G ^{2} - 1}, x = - - \frac{16}{G ^{2} - 1}

Verify Solutions:

x = - \frac{16}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{16}{G ^{2} - 1} {- 1 < G \leq 0}

The solutions are

x = - \frac{16}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{16}{G ^{2} - 1} {- 1 < G \leq 0}

2 x - 3 + 9 = x

3 x^{2} + 1 + 4 = 0

x = 2 x + 8

(m - 14)^{\frac{1}{3}} + 15 = 12

What is the answer to G(x)=sqrt(x^2-16) ?
The answer to G(x)=sqrt(x^2-16) is x=sqrt(-(16)/(G^2-1)) {0<= G<1},x=-sqrt(-(16)/(G^2-1)) {-1<G<= 0}