What is the answer to sqrt((-3-1)^2+(-2-y)^2)=5 ?

The answer to sqrt((-3-1)^2+(-2-y)^2)=5 is y=1,y=-5

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sqrt((-3-1)^2+(-2-y)^2)=5

(- 3 - 1)^{2} + (- 2 - y)^{2} = 5

y = 1, y = - 5

Solution steps

(- 3 - 1)^{2} + (- 2 - y)^{2} = 5

Square both sides:

y^{2} + 4 y + 20 = 25

y^{2} + 4 y + 20 = 25

Solve

y^{2} + 4 y + 20 = 25 : y = 1, y = - 5

y = 1, y = - 5

Verify Solutions:

y = 1

True

, y = - 5

True

The solutions are

y = 1, y = - 5

0.376 = 1 - \frac{1}{x ^{0.62}}

x + 1 - x = 0

3 x + 1 = 2 x - 6

3 x + 1 = 2 x + 1

4 a + 1 + 8 = 3

What is the answer to sqrt((-3-1)^2+(-2-y)^2)=5 ?
The answer to sqrt((-3-1)^2+(-2-y)^2)=5 is y=1,y=-5
Solve for y: sqrt((-3-1)^2+(-2-y)^2)=5
The solution is y=1,y=-5