What is the answer to solvefor y,x=\sqrt[3]{y+1} ?

The answer to solvefor y,x=\sqrt[3]{y+1} is y=x^3-1

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solvefor y,x=\sqrt[3]{y+1}

solve for

y = x^{3} - 1

Solution steps

Take both sides of the equation to the power of

3 : x^{3} = y + 1

x^{3} = y + 1

Solve

x^{3} = y + 1 : y = x^{3} - 1

y = x^{3} - 1

Verify Solutions:

y = x^{3} - 1

True

The solution is

y = x^{3} - 1

2 x + 7 - 13 = - 12

- 2 x + 21 = x - 3

c, 4 + c = 5

125 = r^{2.5}

What is the answer to solvefor y,x=\sqrt[3]{y+1} ?
The answer to solvefor y,x=\sqrt[3]{y+1} is y=x^3-1