What is the answer to \sqrt[4]{7x^2-12}=x ?

The answer to \sqrt[4]{7x^2-12}=x is x=2,x=sqrt(3)

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\sqrt[4]{7x^2-12}=x

x = 2, x = 3

Decimal Notation

x = 2, x = 1.73205 \dots

Solution steps

Take both sides of the equation to the power of

4 : 7 x^{2} - 12 = x^{4}

7 x^{2} - 12 = x^{4}

Solve

7 x^{2} - 12 = x^{4} : x = 2, x = - 2, x = 3, x = - 3

x = 2, x = - 2, x = 3, x = - 3

Verify Solutions:

x = 2

True

, x = - 2

False

, x = 3

True

, x = - 3

False

The solutions are

x = 2, x = 3

731093 = 525600 e^{0.03}

(\frac{x}{1 - x})^{- 0.93} = 1.118

x = 15 - 2 x

16 = 72 m^{\frac{3}{4}}

(1.6 \cdot x^{0.6})^{0.1} = 38

What is the answer to \sqrt[4]{7x^2-12}=x ?
The answer to \sqrt[4]{7x^2-12}=x is x=2,x=sqrt(3)
Solve for x: \sqrt[4]{7x^2-12}=x
The solution is x=2,x=sqrt(3)