What is the answer to 2sqrt(3)=sqrt(u^1+u^2) ?

The answer to 2sqrt(3)=sqrt(u^1+u^2) is u=3,u=-4

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2sqrt(3)=sqrt(u^1+u^2)

23 = u^{1} + u^{2}

u = 3, u = - 4

Solution steps

23 = u^{1} + u^{2}

Square both sides:

12 = u + u^{2}

12 = u + u^{2}

Solve

12 = u + u^{2} : u = 3, u = - 4

u = 3, u = - 4

Verify Solutions:

u = 3

True

, u = - 4

True

The solutions are

u = 3, u = - 4

x, y = x - y

y = 2 y + 9 - 3

4 y - 4 = 9

(a^{2})^{- 1} = a

\frac{x ^{2}}{4} = 2 x + 1

What is the answer to 2sqrt(3)=sqrt(u^1+u^2) ?
The answer to 2sqrt(3)=sqrt(u^1+u^2) is u=3,u=-4
Solve for u: 2sqrt(3)=sqrt(u^1+u^2)
The solution is u=3,u=-4