What is the answer to 9x^{3/2}-18=0 ?

The answer to 9x^{3/2}-18=0 is x=\sqrt[3]{4}

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9x^{3/2}-18=0

9 x^{\frac{3}{2}} - 18 = 0

Decimal Notation

x = 1.58740 \dots

Solution steps

9 x^{\frac{3}{2}} - 18 = 0

Move

18

to the right side

9 x^{\frac{3}{2}} = 18

Divide both sides by

9

x^{\frac{3}{2}} = 2

Take both sides of the equation to the power of

2 : x^{3} = 4

x^{3} = 4

Solve

Verify Solutions:

True

The solution is

x + 2 = 2 + x - 6

- 1 = y + 11 - y

(x^{2} + 4 x + 5)^{\frac{3}{2}} + 1 = 0

x, 2 x + 1 = y + 1

(x x)^{2} = 64

What is the answer to 9x^{3/2}-18=0 ?
The answer to 9x^{3/2}-18=0 is x=\sqrt[3]{4}
Solve for x: 9x^{3/2}-18=0
The solution is x=\sqrt[3]{4}