What is the answer to solvefor x,2sqrt(x+1)=y+1 ?

The answer to solvefor x,2sqrt(x+1)=y+1 is x=(y^2+1)/4+y/2-1 {y>=-1}

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solvefor x,2sqrt(x+1)=y+1

solve for

x, 2 x + 1 = y + 1

x = \frac{y ^{2} + 1}{4} + \frac{y}{2} - 1 {y \geq - 1}

Solution steps

2 x + 1 = y + 1

Divide both sides by

2

x + 1 = \frac{y + 1}{2}

Square both sides:

x + 1 = \frac{y ^{2}}{4} + \frac{y}{2} + \frac{1}{4}

x + 1 = \frac{y ^{2}}{4} + \frac{y}{2} + \frac{1}{4}

Solve

x + 1 = \frac{y ^{2}}{4} + \frac{y}{2} + \frac{1}{4} : x = \frac{y ^{2} + 1}{4} + \frac{y}{2} - 1

x = \frac{y ^{2} + 1}{4} + \frac{y}{2} - 1

Verify Solutions:

x = \frac{y ^{2} + 1}{4} + \frac{y}{2} - 1 {y \geq - 1}

The solution is

x = \frac{y ^{2} + 1}{4} + \frac{y}{2} - 1 {y \geq - 1}

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What is the answer to solvefor x,2sqrt(x+1)=y+1 ?
The answer to solvefor x,2sqrt(x+1)=y+1 is x=(y^2+1)/4+y/2-1 {y>=-1}