What is the answer to x^2=sqrt(2-x^2) ?

The answer to x^2=sqrt(2-x^2) is x=1,x=-1

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x^2=sqrt(2-x^2)

x^{2} = 2 - x^{2}

x = 1, x = - 1

Solution steps

x^{2} = 2 - x^{2}

Square both sides:

x^{4} = 2 - x^{2}

x^{4} = 2 - x^{2}

Solve

x^{4} = 2 - x^{2} : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

True

The solutions are

x = 1, x = - 1

7 x + 22 - x + 19 = 3

3 x - 2 = x + 2

(x + 4)^{\frac{1}{2}} = 1

(x + 4)^{\frac{1}{2}} = 0

5 x + 2 5 - x = 9

What is the answer to x^2=sqrt(2-x^2) ?
The answer to x^2=sqrt(2-x^2) is x=1,x=-1
Solve for x: x^2=sqrt(2-x^2)
The solution is x=1,x=-1