What is the answer to sqrt(x^2+\sqrt{3)}=3^2 ?

The answer to sqrt(x^2+\sqrt{3)}=3^2 is x=sqrt(81-\sqrt{3)},x=-sqrt(81-\sqrt{3)}

Solve for x: sqrt(x^2+\sqrt{3)}=3^2

The solution is x=sqrt(81-\sqrt{3)},x=-sqrt(81-\sqrt{3)}

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x^{2} + 3 = 3^{2}

x = 81 - 3, x = - 81 - 3

Decimal Notation

x = 8.90325 \dots, x = - 8.90325 \dots

Solution steps

x^{2} + 3 = 3^{2}

Square both sides:

x^{2} + 3 = 81

x^{2} + 3 = 81

Solve

x^{2} + 3 = 81 : x = 81 - 3, x = - 81 - 3

x = 81 - 3, x = - 81 - 3

Verify Solutions:

x = 81 - 3

True

, x = - 81 - 3

True

The solutions are

x = 81 - 3, x = - 81 - 3

6 = 2 \cdot x

x - 3 - 2 x + 2 = 2

x, y = x - 4

3 z^{2} - 2 z - 1 = 0

0 = \frac{h}{70}

What is the answer to sqrt(x^2+\sqrt{3)}=3^2 ?
The answer to sqrt(x^2+\sqrt{3)}=3^2 is x=sqrt(81-\sqrt{3)},x=-sqrt(81-\sqrt{3)}
Solve for x: sqrt(x^2+\sqrt{3)}=3^2
The solution is x=sqrt(81-\sqrt{3)},x=-sqrt(81-\sqrt{3)}