What is the answer to sqrt(9-2X)=sqrt(X^2+9) ?

The answer to sqrt(9-2X)=sqrt(X^2+9) is X=0,X=-2

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sqrt(9-2X)=sqrt(X^2+9)

9 - 2 X = X^{2} + 9

X = 0, X = - 2

Solution steps

9 - 2 X = X^{2} + 9

Square both sides:

9 - 2 X = X^{2} + 9

9 - 2 X = X^{2} + 9

Solve

9 - 2 X = X^{2} + 9 : X = 0, X = - 2

X = 0, X = - 2

Verify Solutions:

X = 0

True

, X = - 2

True

The solutions are

X = 0, X = - 2

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- 13 = - 3 v^{- 0.8}

\frac{x}{5} = 3

4 x - 4 = 3 x + 6

What is the answer to sqrt(9-2X)=sqrt(X^2+9) ?
The answer to sqrt(9-2X)=sqrt(X^2+9) is X=0,X=-2
Solve for X: sqrt(9-2X)=sqrt(X^2+9)
The solution is X=0,X=-2