What is the answer to solvefor q=sqrt(Fd+4),d ?

The answer to solvefor q=sqrt(Fd+4),d is d=(q^2-4)/F

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solvefor q=sqrt(Fd+4),d

solve for

q = F d + 4, d

d = \frac{q ^{2} - 4}{F}

Solution steps

q = F d + 4

Square both sides:

q^{2} = F d + 4

q^{2} = F d + 4

Solve

q^{2} = F d + 4 : d = \frac{q ^{2} - 4}{F}

d = \frac{q ^{2} - 4}{F}

2 x - 5 - x - 1 = 2

4 - 2 x + 0.5 = - 10

x, 3 x + y = 0

4 x + 9 - 6 x = 3

What is the answer to solvefor q=sqrt(Fd+4),d ?
The answer to solvefor q=sqrt(Fd+4),d is d=(q^2-4)/F